WebFind the tangent equation to the parabola x_2 = 20y at the point (2, -4): Solution: X_2 = 20y Differentiate with respect to “y”: 2x (dx/dy) = 20 (1) m = dx / dy = 20/2x ==> 5/x So, slope at the point (2, -4): m = 4 / (-4) ==> -1 Equation of Tangent line is: (x – x_1) = m (y – y_1) (x – (-4)) = (-1) (y – 2) x + 4 = -y + 2 y + x – 2 + 4 = 0 WebCalculus: Integral with adjustable bounds. example. Calculus: Fundamental Theorem of Calculus
First and Second Derivative of Parametric Equations - Concavity
WebNov 2, 2024 · Consider the plane curve defined by the parametric equations x = x(t) and y = y(t). Suppose that x′ (t) and y′ (t) exist, and assume that x′ (t) ≠ 0. Then the derivative dy dx is given by dy dx = dy / dt dx / dt = y′ (t) x′ (t). Proof … thirsk \\u0026 northallerton gc
Cartesian to Polar Calculator - Symbolab
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